Using the Pythagorean Theorem :
[tex]c^2=a^2+b^2[/tex]
Where c is the longest side or the hypotenuse
and
a and b are the legs of the right triangle
From the given figure,
The hypotenuse is 7 and one of the legs is 4
so c = 7 and a = 4
Using the formula above, solve for the value of the other leg.
[tex]\begin{gathered} c^2=a^2+b^2 \\ 7^2=4^2+b^2 \\ 49=16+b^2 \\ 49-16=b^2 \\ b^2=33 \\ b=\sqrt[]{33} \end{gathered}[/tex]
Therefore, the third side is sq
