In the question, we are asked to write the equation of a line that passes through the point (-1, 4) with slope 5/6. This can be seen below.
Explanation
The formula is given as
[tex]y-y_1=m(x-x_1)[/tex]y=y coordinate of second point
y_{1}=y coordinate of point one
m=slope
x=x coordinate of second point
x_{1}=x coordinate of point one
Therefore
[tex]\begin{gathered} y-4=\frac{5}{6}(x-(-1)) \\ y-4=\frac{5}{6}(x+1) \end{gathered}[/tex]Answer:
[tex]y-4=\frac{5}{6}(x+1)[/tex]