Given the inequality
[tex]3x+2y>-2[/tex]
For that, first graph the line 3x + 2y = -2.
Identify two points from the line.
When x = 0, y = -1. So, first point is (0, -1).
When y = 0, x = -2/3. So, the second point is (-2/3, 0).
Plot the points and join to get the graph of the line. Since the inequality is strict, the line is not included. So, use dotted lines to graph the line.
Now, take the point (0,0). Plug the point into the inequality gives 0 > -2. So, (0,0) satisfies the inequality. Hence shade the region that contains (0,0), which will be the required region.
