A woman pulls a luggage with a force of 10 N with the angle between theforce and the vertical of 60°. Find the horizontal component of the force.



Answer :

Given

F: Force

F = 10 N

angle = 60

Find the horizontal component of the force.

[tex]\begin{gathered} F=10N\cdot\sin 60 \\ F_x=8.66N \\ \end{gathered}[/tex]

The horizontal x-axis is Fx = 8.66N

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