a golf ball is hit with a velocity of 24.5 m/s at 35 degrees above the horizontal. find the range of the ball and the maximum height of the ball.



Answer :

The range of the ball is equal to 57.23 m and the maximum height of the ball is equal to 10.1 m.

What is the projectile motion?

In the projectile motion, a projectile ion is a flight after being projected and the acceleration is in the vertical direction due to gravity. The vertical motion of the projectile is affected by gravity.

The initial velocity of the golf ball, u = 24.5 sin 35° -= 14.05 m/s

The vertical displacement of a golf ball, S = 0

The gravitational acceleration of the ball, a = -g = -9.81 m/s²

From the 2nd equation of motion:

S = ut - (1/2) ×gt²

0 =  ut - (1/2) ×gt²

(14.05) ×t = (1/2) ×(9.81)t²

t = 2.86 sec

The range of the golf ball, [tex]u_x = 24.5 \times cos 35^o = 20.1 m/s[/tex]

[tex]x= u_xt= 20.1 \times 2.86\\x = 57.23m[/tex]

At the maximum height of the golf ball, the velocity, v = 0

From 3rd equation of motion: v² = u²+ 2aS

S =  (v² - u²)/2a

S =  (0² - (14.05)²)/2(-9.81)

S = 10.1 m

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