Answer:
q(x) = x^2 - 4x + 1
r(x) = 0
b(x) = x - 3
Explanation:
Let us do the polynomial long division.
This tells us
[tex]x^3-7x^2+13x-3=\left(x-3\right)\left(x^2-4x+1\right)+0[/tex]
dividing both sides by x - 3 gives
[tex]\frac{x^3-7x^2+13x-3}{x-3}=\frac{\left(x-3\right)\left(x^2-4x+1\right)}{x-3}+\frac{0}{x-3}[/tex][tex]\boxed{\frac{x^3-7x^2+13x-3}{x-3}=(x^2-4x+1)+\frac{0}{x-3}.}[/tex]
The above tells us that
q(x) = x^2 - 4x + 1
r(x) = 0
b(x) = x - 3.
which are our answers!
