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h(t)=t^2+4t+31.) what are the zeros of the function? write the smaller t first, and the larger t second. smaller t= _____larger t= ____2.) what is the vertex of the parabola? (___,___)



Answer :

The function is:

[tex]h(t)=t^2+4t+3[/tex]

1.

To find the zeros, we factorize it. Shown below:

[tex]\begin{gathered} t^2+4t+3 \\ (t+1)(t+3)=0_{} \\ t+1=0,t=-1 \\ t+3=0,t=-3 \end{gathered}[/tex]

Zeros are:

[tex]t=-3,t=-1[/tex]

2.

Let's sketch the function:

You can see that the vertex is:

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