The work done by the external force on the spring will be 1.67 J
As
F = mg.....(i)
m is mass and g is gravitational acceleration.
F = kx ....(ii)
k is spring constant and x is length.
Equating eq (i) and (ii).
mg = kx
k = mg/x
k = 2×10/6×10^-2
k = 1/3 ×10^3
Now to calculate the work done:
Work done W = 0.5kx²
W = 0.5 × 1/3 ×10^3 × 0.1^2
W = 1.67 J
The work done by the external force on the spring will be 1.67 J
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