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A spring has a spring constant of 100 N/m. When the spring is compressed by 5 mm (such that \Delta xΔx is negative), determine the restoring spring force.

A spring has a spring constant of 100 Nm When the spring is compressed by 5 mm such that Delta xΔx is negative determine the restoring spring force class=


Answer :

Given that spring constant, k = 100 N/m and displacement, x = - 5mm = - 0.005 m

The formula of restoring force according to Hooke's law,

[tex]F=-kx[/tex]

Substituting the values, we get

[tex]\begin{gathered} F=-100(-0.005) \\ =\text{ 0.5 N} \end{gathered}[/tex]

Thus, the force is 0.5 N

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