Answer :
The first answer is If the nitrogen source is cut by 90 percent, 0.0158 mg/l algae are produced. The answer to the second part is If the Phosphorus source is cut by 90 percent, 0.458 mg/L of algae is produced
a)0.10 mg N(1/10) = 0.001 mg N
Because the limiting nutrient decreases in concentration N will still be the limiting nutrient
(0.001mg N / 1L water)*(1000 mg algae/63.1 mg N) = 0.0158 mg/l algae
If the nitrogen source is cut by 90 percent, 0.0158 mg/l algae are produced.
b) If the Phosphorus source is cut by 90 percent
0.04 mg P(1/10) = 0.004 mg P
Amount of N produced is still 0.10 mg/L
Thus supply ratio = 0.10 mg N/ 0.004 mg P = 25
P is now limiting nutrient
(0.004 mg P /1L water) * ( 1000mg algae / 8.724 mg P) = 0.458 mg/L of algae is produced
More about limiting nutrients and eutrophication
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