a 870-kg car starts from rest on a horizontal roadway and accelerates eastward for 5.00 s when it reaches a speed of 30.0 m/s. what is the average force exerted on the car during this time?



Answer :

Qwdog

The force exerted by the car during the 5s acceleration is 5,220 N

The mass of the car, m = 870 kg

The car accelerated towards the east for 5 seconds

Speed of the car = 30 m/s

The force exerted by the car can be found using the formula

               Force = mass x acceleration

But we know that

                    Acceleration = velocity / time

Therefore, the force formula becomes

                  F = (m x v) / t

where F is Force

          m is mass

          v is velocity and

          t  is the time period

Let us substitute the known values in the above formula, we get

       

                         F = 870 x 30 / 5

                            = 26,100 / 5

                        F  = 5,220 N

Therefore, the force exerted by the car is 5,220 N

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