An object with mass m and speed v relative to an observer, explodes into two pieces, one three times as massive as the other; the explosion takes place in deep space. The less massive piece stops relative to the observer. How much kinetic energy is added to the system during the explosion, as measured in the observers reference frame?



Answer :

The energy added to the system due to the explosion in the observer's frame of reference will be given by: Eadd = 1/6 mv²

Law of conservation of linear momentum : -

The law of conservation of linear momentum asserts that the vector sum of a system of two colliding objects is constant and unaffected by their mutual interaction when no external forces are acting on the system.

The object's mass is m.

v is the object's velocity in relation to a stationary observer.

As a result, k= 1/2 mv2 will be used to calculate the object's initial kinetic energy in the observer's frame of reference.

The thing detonates.

Let m represent the mass of the piece with less mass.

Therefore, mh=3ml will provide the mass of the larger piece.

Following the explosion, the lighter piece moves at a speed of vl=0 and the less massive piece comes to a standstill.

Let vh=0 represent the speed of the larger piece following the explosion.

Applying the equation of conservation of linear momentum to the system's explosion and one-dimensional motion, we can now write:

Therefore, the energy added to the system due to the explosion in the observer's frame of reference will be given by:

E add = Kf-Ki

Eadd= 2/3 mv² - 1/2 mv²

Eadd = 1/6 mv²

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