The question requires us to calculate the volume of a gas when its pressure is kept constant and its temperature is raised from 200 to 600 K.
The following information was provided by the question:
Initial volume of gas = V(1) = 6.00 L
Initial temperature of gas = T(1) = 200 K
Final temperature of gas = T(2) = 600 K
According to Charle's Law, the volume of a given confined gas under constant pressure increases as the temperature increases and decreases as the temperature decreases. In other words, the Charle's Law states that the volume of a given amount of gas is directly proportional to its temperature on the kelvin scale when the pressure is held constant
Mathematically, we can write this as:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]where V(1) and T(1) refers to the volume and temperature of the gas at the initial state, and V(2) and T(2) refers to volume and temperature at the final state.
We can rearrange the equation above in order to calculate the final volume of a gas:
[tex]V_2=\frac{V_1\times T_2_{}}{T_1}[/tex]Now, we can apply the values given by the question to this equation and calculate the final volume of the gas:
[tex]V_2=\frac{(6.00L)\times(600K)}{(200K)}=18.0L[/tex]Therefore, the final volume of the gas when the temperature is increased under constant pressure is 18.0 L and the best option to answer this question is letter D.