Consider the balanced chemicalreaction below and determine thepercent yield for carbon dioxide if 4.50moles of propane yielded 7.64 moles ofcarbon dioxide.C3H8 +502 + 3CO2 + 4H2O-→

Consider the balanced chemicalreaction below and determine thepercent yield for carbon dioxide if 450moles of propane yielded 764 moles ofcarbon dioxideC3H8 502 class=


Answer :

To solve this, we must know some terms:

% Yield = (Actual yield / Theoretical yield) x 100

Actual yield is already given = 7.64 moles

To obtain the theoretical yield, we use stoichiometry and proceed like this:

C3H8 + 5O2 => 3CO2 + 4H2O

1 mole C3H8 ------- 3 x 1 mole CO2

4.5 moles C3H8 ------ x

x = 13.5 moles

Therefore, our % yield:

% Yield = (7.64 moles/13.5 moles) x 100 = 57 % approximately

Answer: % yield = 57 %