Answer:
T = 101.96 degrees
Explanation:
We are given the following
Number of moles = 0.650 mol
Volume = 1.00 L
Pressure = 20.00 atm
We are going to use the ideal gas low which is given by:
pV = nRT
Therefore:
[tex]T\text{ = }\frac{pV}{nR}[/tex]We know R = 0.08206 L.atm/Kmol
[tex]\begin{gathered} T\text{ = }\frac{20\ast1}{0.65\ast0.08206} \\ T\text{ = 374.960 K} \end{gathered}[/tex]T(in degrees) = 374.96 - 273
= 101.96 degrees