Given: An AP whose first term is -20 and a common difference of 3.
Required: To determine the 119th term of the AP.
Explanation: An AP with the first term, a, and with a common difference, d, is of the form-
[tex]a,a+d,a+2d,...,a+(n-1)d[/tex]
where n is the number of terms in the AP.
The following formula gives the nth term of the AP-
[tex]a_n=a+(n-1)d[/tex]
Here it is given that-
[tex]\begin{gathered} a=-20 \\ d=3 \\ n=19 \end{gathered}[/tex]
Substituting these values into the formula for nth terms as-
[tex]a_{19}=-20+(19-1)3[/tex]
Further solving-
[tex]\begin{gathered} a_{19}=-20+54 \\ =34 \end{gathered}[/tex]
Final Answer: The 19th term of the AP is 34.
