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Which answer shows how to solve the given equation using the quadratic formula? 22 - 3. - 4= 0 3+, 22-4(2)(-4) 2(2) -(-3)=1/(-3)2-4(2)(-4) 2(2) 4+/(-3) -4(2)(-4) 2 3+1/32-4(-3)(-4) 2(2)



Answer :

hello

the question here is a given quadratic equation and we're required to use quadratic formula to solve it.

[tex]2x^2-3x-4=0[/tex]

now, to solve this, let's bring out quadratic formula first

[tex]x=-b\pm\frac{\sqrt[]{b^2-4ac}}{2a}[/tex]

now from our equation given, we can easily identify a, b and c.

[tex]\begin{gathered} 2x^2-3x-4=0 \\ a=2 \\ b=-3 \\ c=-4 \end{gathered}[/tex]

next we plug in the variables into the equation and solve

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