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3. x-intercept 4, y-intercept 2, passes through 5. Center on x = 3, radius 13, passes through Center on the y-axis, radius 5, x-intercept 3 cle having the given center and radius. (b) C (-2,-5), r = 4 (d) C(2, -3), r= 6 ving the given properties. (0,0) (6, 5)



Answer :

Samantha, this is the solution to problem 5:

With the information given in the statement you can solve for k, where k is the center in y:

(x-h)^2 + (y-k)^2 = r^2

(6-3)^2 + (5-k)^2 = (√(13))^2

(3)^2 + (5-k)^2 = 13

9+(5-k)^2 = 13

(5-k)^2 = 4

√((5-k)^2) = √4

5-k = 2

-k = -3

k = 3

Then the equation of the circle will be

(x-3)^2 + (y-3)^2 = 13

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