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Find the coordinates of the center, vertices, covertices, foci, length of transverse and conjugate axis and the equation of the asymptotes. Then graph the hyperbola.

Find the coordinates of the center vertices covertices foci length of transverse and conjugate axis and the equation of the asymptotes Then graph the hyperbola class=


Answer :

The given equation is,

[tex]\frac{x^2}{36}-\frac{y^2}{16}=1\text{ ---(1)}[/tex]

It can be rewritten as,

[tex]\frac{x^2}{6^2}-\frac{y^2}{4^2}=1\text{ ---(2)}[/tex]

The above equation is similar to the standard equation of left-right facing a hyperbola given by,

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