a simple pendulum consists of an object suspended by a string. the object is assumed to be a particle. the string, with its top end fixed, has negligible mass and does not stretch. in the absence of air friction, the system oscillates by swinging back and forth in a vertical plane. if the string is 1.40 m long and makes an initial angle of 31.0° with the vertical, calculate the speed of the particle at the following positions.



Answer :

The angular speed of the pendulum is √7 rad/s.

We need to know about pendulum experiments to solve this problem. The pendulum is a simple experiment to calculate gravitational acceleration. The gravitational acceleration can be calculated by

g = 4π² . L / T²

where g is gravitational acceleration, L is the length of the string and T is the period.

From the question above, we know that:

L = 1.40 m

g = 9.8 m/s²

θmax = 31°

m = m

Find the period of pendulum

g = 4π² . L / T²

9.8 = 4π² . 1.4 / T²

T² = 4π²/7

T = 2π√7 / 7 s

Find the angular speed

ώ = 2π / T

ώ = 2π / (2π√7 / 7)

ώ = √7 rad/s

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