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A 2. 55 kg bucket of sand is attached to a 1. 31 m long rope and is swung in a vertical circle. At the bottom of the circle the tension in the rope is 30. 2 n. What is the speed of the bucket of sand at the bottom of the circle?.



Answer :

When a 2. 55 kg bucket of sand is attached to a 1. 31 m long rope and is swing in a vertical circle. At the bottom of the circle, the tension in the rope is 30. 2 n. Then the speed at which the bucket will move at the bottom of the circle will be 4.13 m/s

Here,

m=2.55kg

r=1.31m

T=30.2 N

Now,

T - mg = m(v^2/r)

Putting the known value in this equation we get;

30 - 2.55*g = 2.55(v^2/1.31)

30-24.99 = 1.94v²

1.94v² = 5.01

v² = 17.11

v = 4.13

Therefore the speed at the bottom of the circle will be 4.13 m/s.

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