Perform calculations to determine the amount of 50.0 mM Ca(NO3)2 needed to prepare 20.0 mL of 5.00 mM Ca(NO3)2. Perform calculations to determine the amount of 5.00 mM Ca(NO3)2 needed to prepare 20.0 mL of 1.00 mM Ca(NO3)2. Perform calculations to determine the amount of 1.00 mM Ca(NO3)2 needed to prepare 20.0 mL of 0.250 mM Ca(NO3)2.



Answer :

The required volumes are;

1)  2 mL

2)  4 mL

3)  5 mL

What is the amount needed?

Now we know that the dilution formula can be used to obtain the quantity of a solution that could be used in the preparation of another by the use of serial dilution. In this case, we can see that an aliquot of the solution is taken and then made up to mark in order to obtain the concentration that we require as we are trying to carry out the process of the serial dilution.

Now let us try to see how we can be able to prepare the solutions that are required as follows;

To prepare 50mM of of calcium nitrate;

C1V1= C2V2

C1 = initial concentration’

V1 = initial volume

C2 = final concentration

V2 = final volume

C1 = C2V2/C1

C1 = 20.0 mL *  5.00 mM/50mM

C1 = 2 mL

2) 20.0 mL *  1.00 mM/ 5.00 mM

= 4 mL

3) 20.0 mL *  0.250 mM/1.00 mM

= 5 mL

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