The volume of the sample, given the data from the question is 97.7 mL
How to determine the mole of nitrate ion, NO₃⁻
We'll begin by obtaining the mole of the nitrate ion, NO₃⁻ that contains 2.53×10²² ions. This can be obtained as follow:
From Avogadro's hypothesis,
6.02×10²³ ions = 1 mole of NO₃⁻
Therefore,
2.53×10²² ions = (2.53×10²² ions × 1 mole) / 6.02×10²³ ions
2.53×10²² ions = 0.042 mole of NO₃⁻
How to determin the mole of Co(NO₃)₂
Co(NO₃)₂(aq) --> Co²⁺(aq) + 2NO₃⁻(aq)
From the equation above,
2 moles of NO₃⁻ is present in 1 mole of Co(NO₃)₂
Therefore,
0.042 mole of NO₃⁻ will be present in = 0.042 / 2 = 0.021 mole of Co(NO₃)₂
How to determine the volume of the sample
- Mole of Co(NO₃)₂ = 0.021 mole
- Molarity of Co(NO₃)₂ = 0.215 M
- Volume = ?
Molarity = mole / volume
Thus,
Volume = mole / molarity
Volume = 0.021 / 0.215
Volume = 0.0977 L
Multiply by 1000 to express in mL
Volume = 0.0977 × 1000
Volume = 97.7 mL
Thus, the volume of the sample is 97.7 mL
Learn more about number of ion and molarity:
https://brainly.com/question/15370276
https://brainly.com/question/14295820
#SPJ1
