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Pb in tetraethyl lead, Pb(C2H5)4 (once extensively used as an additive to gasoline to prevent engine knocking)
Express your answer using four significant figures. Determine the percent,by mass, for Pb



Answer :

mickymike92

The percent mass of lead in tetraethyl lead is 64.1%.

What is the percent by mass of Pb in tetraethyl lead, Pb(C₂H₅)₄?

The percent by mass of an element in a compound is determined by taking the ratio of the atomic mass of the element and the molar mass of the compound and then multiply by 100%

  • Percent mass = (atomic mass of element/molar mass of compound) * 100%

atomic mass of Pb = 207

atomic mass of C = 12

atomic mass of H = 1

Molar mass of  tetraethyl lead: 207 + 12 * 2 * 4  + 1 * 5 * 4

Molar mass of  tetraethyl lead = 323 g/mol

Percent mass of Pb = 207/323 × 100%

Percent mass of Pb = 0.6408 × 100%

Percent mass of Pb = 64.1%

In conclusion, the percent mass of lead in tetraethyl lead is 64.1%.

Learn more about percent mass at: brainly.com/question/5394922

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