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two identical small conducting spheres are separated by 0.60 m. the spheres carry different amounts of charge and each sphere experiences an attractive electric force of 10.8 n. the total charge on the two spheres is ­24 μc. the two spheres are now connected by a slender conducting wire, which is then removed. the electric force on each sphere is closest to



Answer :

The correct answer is 3.6N repulsive.

One of the fundamental forces of the cosmos is electrostatic force. The universe is governed by four fundamental forces. They are gravitational force, weak nuclear force, electromagnetic force, and strong nuclear force. Under electromagnetic force is the electrostatic force. Between two charges that are separated by a distance, there is an electrostatic force. The size of each charge and the separation between them determine the strength of the electrostatic force.

Given r=0.60m

F=10.8N

F=k q_1q_2/r^2=-10.8N_____(1)

q_1+q_2=-24_____(2)

solving 1 and 2

we get q_1, q_2

=12μC and -36μC

when joined with wire each sphere carries

q_1+q_2/2=-12μC

Electric force = kq_1q_2/r^2

=3.6N repulsive

To learn more about electrostatic force refer the link:

https://brainly.com/question/15369218

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