Suppose two individuals with the genotype A a B b C c are mated. Assuming that the genes are not linked, what fraction of the offspring are expected to be homozygous recessive for the three traits? (A) 1 / 4 (B) 1 / 8 (C) 1 / 16 (D) 1 / 64

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23-08-2022
Biology

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Suppose two individuals with the genotype A a B b C c are mated. Assuming that the genes are not linked, what fraction of the offspring are expected to be homozygous recessive for the three traits? (A) 1 / 4 (B) 1 / 8 (C) 1 / 16 (D) 1 / 64

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AnnuG AnnuG · Answer 1 · 2022-08-31T06:39:47-04:00

Correct option (B) 1 / 8

This fraction of offspring are expected to be homozygous recessive by the traditional method of solving this problem can be using punnett square. Punnett square of normal trihybrid cross.

Genotype AABBCC will produced only one type of gamete which is ABC. The frequency for production of ABC gamete is 1. Genotype AaBbCc can produced eight type of gametes such as ABC, Abc, ABc, AbC,abc, aBc, aBc and abC. Heterozygous cross will occur only when abc gamete from AaBbCc present fertilises with ABC gamete from AABBCC.

The hybrid for all the three genes AaBbCc=1/8. The probabiulity of aabb offspring when AaBb parents are crossed is 1/16.

To learn more about punnett square here

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