A ball is thrown straight out at 80 feet per second from an upstairs window that's 15 feet off the ground .the horizontal distance of the ball from the window at the moment it strikes the ground is 77.6 feet .
Here what we know in the y-direction :
a= -32 ft/s/s
U= 0 (initial velocity of ball )
S = -15 feet
according to equation of displacement ,
[tex]S=Ut+\frac{1}{2} at^{2}[/tex]
[tex]-15=0\times t +\frac{1}{2} \times( -32)t^{2}[/tex]
[tex]t=\sqrt{\frac{15}{16} }[/tex]
t=0.9682 sec
t=0.97 sec
now we use that time in x-direction .
here,
a=0
U= 80 ft/s
t=0.97s
Now according to displacement formula,
S = 80 ( 0.97) + 0( 0.97) (0.97)
S= 77.6 feet
Hence the ball's horizontal distance from the window at the moment it strikes the ground is 77.6 feet .
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