Answered

The height, in feet, of a ball t seconds after it is thrown upward is given by height
= −10t2 + 89t + 3. Find the height of the ball 2 seconds after it has been released.
ft



Answer :

MrRoyal

The height of the ball 2 seconds after it has been released is 141 feet

How to find the height of the ball 2 seconds after it has been released?

The height function is given as:

h(t) = −10t^2 + 89t + 3

At 2 seconds, we have

t = 2

So, the equation becomes

h(2) = −10 * 2^2 + 89 * 2 + 3

Evaluate the exponent and the product

h(2) = −40 + 178 + 3

Evaluate the sum and the difference

h(2) = 141

Hence, the height of the ball 2 seconds after it has been released is 141 feet

Read more about height functions at

https://brainly.com/question/12446886

#SPJ1

Other Questions