Answer :

kate200468
[tex]5^2+4^2=25+16=41\\\\5\cdot8+1=40+1=41[/tex]
[tex]\frac{31-11}{2}\times4+1=\frac{20}{2}\times4+1=10\times4+1=40+1=41\\\\(2+4)^2+2^2+(123\times298)^0=6^2+4+1=36+4+1=41[/tex]
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