let A ---> (-3, 8) B ---> (2, 8) C----> (2, -2) D----> (-3, -2)
step 1 find the distance AB d=√[(y2-y1)²+(x2-x1)²]-----> d=√[(8-8)²+(2+3)²]----> d=√25-----> d=5 units
step 2 find the distance BC d=√[(y2-y1)²+(x2-x1)²]-----> d=√[(-2-8)²+(2-2)²]----> d=√100-----> d=10 units
step 3 find the ratio of the rectangle's length to its width ratio=rectangle's length/rectangle's width length=10 units width=5 units ratio=10/5-----> ratio=2
the answer is the ratio of the rectangle's length to its width is 2
