Answered

A compact disc rotates from rest up to an angular speed of 31.4rad/s in a time of 0.8972s. Through what angle does the disc turn while coming up to speed.



Answer :

MathPhys

Answer:

14.1 rad

Explanation:

Assuming constant acceleration, we can use kinematic equations to find the angular displacement as a function of the angular velocities and time.

Given:

ω₀ = 0 rad/s

ω = 31.4 rad/s

t = 0.8972 s

Find: Δθ

Δθ = ½ (ω + ω₀) t

Δθ = ½ (31.4 rad/s + 0 rad/s) (0.8972 s)

Δθ = 14.1 rad

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