Example Stem 1: A system of two linear equations has no solution.
The first equation is 3x + y = -2. Select the second equation that
would make this system have no solution.
A. 2x+y= 4
B. 2x + y = 5
C. 3x+y= = 4
D. 4x + y = 5
(3-)
(1-E) 0


please helpppppp



Answer :

Answer:

C.  3x + y = 4  

Step-by-step explanation:

For a system of equations to have no solutions implies that the graphs of these equations do not intersect

The equation 3x + y = - 2 is the equation of a straight line

In slope-intercept form we can re-write this as:
y = - 3x -2    (subtract 3x from both sides)

The slope of this line is - 3

For another straight line not to intersect, it must have the same slope and a different intersect

So its equation will be of the form
y = - 3x + c    where c is some constant

Adding 3x to both sides gives us
3x + y = c

The only equation that has 3x as a term is

C.  3x + y = 4

i am not sure if that second = sign is a negative sign. Either way the answer is C