Answer :

b) [tex]-\sqrt{3}[/tex] ; d) 0: f) 0; h) [tex]\sqrt{2}[/tex]; j) [tex]-\sqrt{2} /2[/tex]

======================

b) cot 150°

In the second quadrant, the cosine is negative, and the sine is positive, which makes the cotangent (cos/sin) negative.

  • cot 150° = cot (180°-30°) = -cot 30° = [tex]-\sqrt{3}[/tex]

d) cos (7π/2)

This is equivalent to cos (2π + π/2), which is cos (π/2). Cosine is zero at π/2, so,

  • cos (7π/2) = cos (π/2) = 0.

f) sin (6π)

Since sine has a period of 2π, sin (6π) is the same as sin (0), which is

  • sin (6π) = 0

h) sec (-7π/4)

This is the reciprocal of the cosine.

cos (-7π/4) is the same as cos (π/4) = [tex]\sqrt{2} /2[/tex], since cosine is even and has a period of 2π.

Therefore,

  • sec (-7π/4) = 1/ ([tex]\sqrt{2} /2)[/tex] = [tex]\sqrt{2}[/tex]

j) csc (- 45°)

The cosecant is the reciprocal of the sine.

Since sine is odd, sin (-45°) is -sin (45°), which is [tex]-\sqrt{2} /2[/tex].

Thus,

  • csc (- 45°) =  [tex]-\sqrt{2} /2[/tex]