Let s(t) = −2t² + 2t + 8 where s represents the position (displacement), at time t, of an object moving on a straight line, where t is measured in seconds. Consider such an object over the time interval [0,1].

Determine the position of the object at t=0 and t=1.

The object's position at t = 0 is ___ feet
The object's position at t = 1 is ___ feet



Answer :

Answer: s(0) = 8; s(1) = 8

Step-by-step explanation:

To find the object's position at a given time, we can simply plug in the value of t into the equation for position everywhere there is a t.

Let's calculate the object's position at t = 0:

s(0) = -2(0)² + 2(0) + 8

s(0) = 0 + 0 + 8

s(0) = 8

The object's position at t = 0 is 8 feet.

Let's calculate the object's position at t = 1:

s(1) = -2(1)² + 2(1) + 8

s(1) = -2 + 2 + 8

s(1) = 0 + 8

s(1) = 8

The object's position at t = 1 is 8 feet.

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