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A system of equations is given. Solve for (x,y) using the elimination method.
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`-2y=2-3x`

`-5y=10-5x`



Answer :

Answer:

(6/7, 2/7) or x=6/7, y=2/7

Step-by-step explanation:

[tex]\left \{ {{-2y=2-3x} \atop {-5y=10-5x}} \right.[/tex]

[tex]\left \{ {{-10y=10-15x} \atop {10y=-20+20x}} \right.[/tex]

add them

10-15x=-20+20x

35x=30

x=6/7

plug it in

-2y=2-18/7

-2y=-4/7

y=2/7

sqdancefan

Answer:

  (x, y) = (-2, -4)

Step-by-step explanation:

You want to solve the system of equations ...

  • -2y = 2 -3x
  • -5y = 10 -5x

Elimination

To use this method of solving the equations, we need two equations that have opposite coefficients for one of the variable.

Here, it is convenient to divide the second equation by -5, then multiply it by 2:

  y = -2 +x

  2y = -4 +2x

Adding this to the first equation eliminates y:

  (2y) +(-2y) = (-4 +2x) +(2 -3x)

  0 = -2 -x

  x = -2 . . . . . . . . add x

Using our equation for y above, we find ...

  y = -2 +x = -2 -2

  y = -4

The solution is (x, y) = (-2, -4).

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