Answered

What’s the function f(x) is divided by 3x+8, the quotient is 2x^6-4x+1 and the remainder is 9. Find the function f(x) and write the result in standard form.

Whats the function fx is divided by 3x8 the quotient is 2x64x1 and the remainder is 9 Find the function fx and write the result in standard form class=


Answer :

Quad12364

Answer: f(x) = 2x^5 - 4x^3 + x^2 - 4x + 10

Step-by-step explanation:

In order to solve this problem, we will first divide the given function f(x) by 3x+8 and then find the quotient and remainder. After that, we will write the result in the standard form.

Given: f(x) = 2x^6 - 4x + 1

Quotient: 2x^6 - 4x + 1 ÷ (3x + 8) = 2x^5 - 4x^3 + 1x^2 - 4x + 1

Remainder: R = 9

Now, we will combine the quotient and the remainder to find the function f(x).

f(x) = 2x^5 - 4x^3 + 1x^2 - 4x + 1 + 9

f(x) = 2x^5 - 4x^3 + 1x^2 - 4x + 10

Therefore, the function f(x) can be written in the standard form as:

f(x) = 2x^5 - 4x^3 + x^2 - 4x + 10

Other Questions