A plane travels 600miles from Salt Lake City, Utah, to Oakland, California, with a prevailing wind of 50mph . The return trip against the wind takes1/2 hour longer. Find the average speed of the plane in still air.



Answer :

Answer:

  350 mph

Step-by-step explanation:

You want the speed of a plane in still air if a trip of 600 miles with a 50 mph wind is 1/2 hour shorter than the same trip against the wind.

Time

The relation between time, speed, and distance is ...

  t = d/s

If p is the speed of the plane, then its speed with the wind is (p+50) and its speed against the wind is (p-50).

The difference in times for the two trips is ...

  600/(p-50) -600/(p+50) = 1/2

Solution

  600(1/(p-50)-1/(p+50)) = 1/2

  ((p+50)-(p-50))/((p-50)(p+50)) = 1/1200 . . . . . divide by 600

  p² -50² = 120000 . . . . combine fractions, invert both sides

  p = √122500 = 350

The speed of the plane in still air is 350 mph.

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Additional comment

The trip to Oakland takes 1 1/2 hours; the return takes 2 hours.