Answer:
For the cylinder:
V = πr²h
d = 6
r = 3 inches
V = πr²h
V = πr3²h
V = 9πh
Given data:
Since the tank holds 26 pounds of oil:
V = 26
26 = 9πh
[tex]h = \frac{26}{9\pi}[/tex]
Total area (At):
At = 2Ab + Al
Where:
Ab: base area
Al : lateral area
Calculating Ab
Ab =πr²
Ab = π3²
Ab = 9π in²
Al = 2πrh
[tex]Al = \frac{2\pi \times 3 \times 26}{9\times \pi} \\ \\ \\Al = \frac{2\times 3 \times 26}{9} \\ \\ \\Al = \frac{52}{3}[/tex]
Calculating At:
At = 2Ab + Al
At = 2×9π + 52/3
At = 18π + 52/3