Answer:
(c) 4.5×10⁻⁵ AU
Step-by-step explanation:
You want the 6.7×10³ km diameter of the Earth expressed in terms of astronomical units (AU), which are 1.496×10⁸ km.
[tex]\dfrac{6.7\times10^3\text{ km}}{1.496\times10^8\ \dfrac{\vphantom{\overline{B}}\text{km}}{\text{AU}}}}\approx\boxed{4.5\times10^{-5}\text{ AU}}[/tex]
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Additional comment
The diameter is expressed using 2 significant figures, which is fewer than the number expressing the length of an AU. Hence the answer needs to be rounded to 2 significant figures.
As with all units conversion problems, you can think of the conversion factor as an "identity element." Its value is 1, because its numerator (1.496×10⁸ km) is equal to its denominator (1 AU). Multiplying or dividing by such a factor does not change the value. It only changes the units.