Answer :
Let's say the number of males is x. Since the number of females is 15 less, the number of females is x - 15. We know that the total number of students is 33, so x + (x - 15) = 33. Simplifying the equation, we get x = 20 and x - 15 = 5. So, there are 20 males and 5 females in the class.
Answer:
Let's denote the number of males as \(M\) and the number of females as \(F\).
We know that the total number of students is 33:
\[ M + F = 33 \]
The problem also states that the number of females is 15 less than the number of males:
\[ F = M - 15 \]
Now, you can solve these two equations simultaneously to find the values of \(M\) and \(F\).
Substitute the expression for \(F\) from the second equation into the first equation:
\[ M + (M - 15) = 33 \]
Combine like terms:
\[ 2M - 15 = 33 \]
Add 15 to both sides:
\[ 2M = 48 \]
Divide by 2:
\[ M = 24 \]
Now that you know the number of males (\(M\)), substitute this value back into the second equation to find \(F\):
\[ F = 24 - 15 = 9 \]
So, there are 24 males and 9 females in the class.