Triangle TVW is dilated according to the rule
DO, 3/4 (x,y) (3/4x 3/4y to create the image triangle T'V'W', which is not shown.

On a coordinate plane, triangle T V W has points (negative 4, 8), (0, 4), and (4, 4).

What are the coordinates of the endpoints of the segment T'V'?

T'(-3, 6) and V'(0, 3)
T'(-3, 6) and V'(0, 1)
T'(-1, 2) and V'(0, 3)
T'(-1, 2) and V'(0, 1)

Question

06-06-2023
Mathematics

Answered

Triangle TVW is dilated according to the rule
DO, 3/4 (x,y) (3/4x 3/4y to create the image triangle T'V'W', which is not shown.

On a coordinate plane, triangle T V W has points (negative 4, 8), (0, 4), and (4, 4).

What are the coordinates of the endpoints of the segment T'V'?

T'(-3, 6) and V'(0, 3)
T'(-3, 6) and V'(0, 1)
T'(-1, 2) and V'(0, 3)
T'(-1, 2) and V'(0, 1)

Answer :

Other Questions

For Exercises 1–8, refer to the graph. LIMITED TIME UNTIL 11:25!!!! 1. Find f(1). (1,1) 2. Find f(4). (4,2) 3. Write the domain of f. { 1,2,3,4,5,7} 4. Write th

sqdancefan sqdancefan · Answer 1 · 2023-06-06T16:57:32-04:00

Answer:

(a) T'(-3, 6) and V'(0, 3)

Step-by-step explanation:

You want the coordinates of T'V' after segment TV is dilated by a factor of 3/4 about the origin. Points are T(-4, 8) and V(0, 4).

Dilation

The coordinates of the dilated segment can be found using the given transformation:

(x, y) ⇒ (3/4x, 3/4y)

T(-4, 8) ⇒ T'(3/4(-4), 3/4(8)) = T'(-3, 6)

V(0, 4) ⇒ V'(3/4(0), 3/4(4)) = V'(0, 3)

The coordinates of segment T'V' are T'(-3, 6) and V'(0, 3).

<95141404393>