Answer:
b. 5.9 mL
Step-by-step explanation:
You want the value that represents the 99th percentile of a normal distribution with a mean of 5 mL and a standard deviation of 0.4 mL.
The inverse of the normal CDF function is used to find the X value for a given area. Here, we want X such that P(x < X) = 0.99 for μ = 5 and σ = 0.4.
The attached calculator output shows that is about X = 5.9305. Rounded to 1 decimal place, the volume is ...
5.9 mL
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