Find the length of the midsegment of the trapezoid with the vertices S(0, 0), 7(2, 7), U(6, 10), V(8, 6).
The length of the midsegment is

Find the length of the midsegment of the trapezoid with the vertices S0 0 72 7 U6 10 V8 6 The length of the midsegment is class=


Answer :

Answer:

7.5

Step-by-step explanation:

A trapezoid is a quadrilateral where the bases are parallel, but the legs are not parallel.

Given vertices of trapezoid STUV:

  • S = (0, 0)
  • T = (2, 7)
  • U = (6, 10)
  • V = (8, 6)

The parallel bases of the trapezoid are TU and SV.

Find the lengths of TU and SV using the distance formula.

[tex]\boxed{\begin{minipage}{7.4 cm}\underline{Distance between two points}\\\\$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$\\\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are the two points.\\\end{minipage}}[/tex]

[tex]\begin{aligned}TU&=\sqrt{(x_U-x_T)^2+(y_U-y_T)^2}\\&=\sqrt{(6-2)^2+(10-7)^2}\\&=\sqrt{(4)^2+(3)^2}\\&=\sqrt{16+9}\\&=\sqrt{25}\\&=5\end{aligned}[/tex]

[tex]\begin{aligned}SV&=\sqrt{(x_V-x_S)^2+(y_V-y_S)^2}\\&=\sqrt{(8-0)^2+(6-0)^2}\\&=\sqrt{(8)^2+(6)^2}\\&=\sqrt{64+36}\\&=\sqrt{100}\\&=10\end{aligned}[/tex]

The midsegment of a trapezoid is the segment parallel to the bases that connects the midpoints of the legs.

[tex]\boxed{\begin{minipage}{6.5cm}\underline{Midsegment of a Trapezoid}\\\\$M=\dfrac{b_1+b_2}{2}$\\\\where:\\ \phantom{ww}$\bullet$ $M$ is the length of the midsegment. \\\phantom{ww}$\bullet$ $b_1$ and $b_2$ are the parallel bases. \\\end{minipage}}[/tex]

Substitute the found lengths of the bases into the midsegment formula:

[tex]\implies M=\dfrac{5+10}{2}[/tex]

[tex]\implies M=\dfrac{15}{2}[/tex]

[tex]\implies M=7.5[/tex]

The length of the midsegment is 7.5.

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