meredith48034
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Part 3
Graph the polygon with the given vertices and its image after the transformation. Label all vertices in both the image and preimage using the correct notation.

7. A(-4, 3), B(-5, -1), C(0, 2)
Translation:(x, y)--> (x + 2, y + 1)

8. A(-2, -4), B(-2, 4), C(2, 2)
Dilation: k = 1/2



Answer :

mhanifa

Apply the indicated rule for each vertex of the polygon and then graph both the image and preimage.

Question 7

  • A(-4, 3), B(-5, -1), C(0, 2)
  • Translation:(x, y) → (x + 2, y + 1)
  • A(-4, 3) → A'(- 4 + 2, 3 + 1 ) = A'(-2, 4)
  • B(-5, -1) → B'(-5 + 2, - 1 + 1) = B'(-3, 0)
  • C(0, 2) →  C'(0 + 2, 2 + 1) = C'(2, 3)

Question 8

  • A(-2, -4), B(-2, 4), C(2, 2)
  • Dilation: k = 1/2
  • A(-2, - 4) → A'(-2/2, - 4/2) = A'(-1, - 2)
  • B(-2, 4) → B'(-2/2, 4/2) = B'(-1, 2)
  • C(2, 2) → C'(2/2, 2/2) = C'(1, 1)

See attached for both.

View image mhanifa
View image mhanifa
semsee45

Answer:

Question 7:

  • A' (-2, 4)
  • B' (-3, 0)
  • C' (2, 3)

Question 8:

  • A' (-1, -2)
  • B' (-1, 2)
  • C' (1, 2)

Step-by-step explanation:

Question 7

Given vertices of the pre-image:

  • A = (-4, 3)
  • B = (-5, -1)
  • C = (0, 2)

Given transformation rule:

  • [tex](x, y) \rightarrow (x + 2, y + 1)[/tex]

Therefore the vertices of the image are:

  • A' = (-4 + 2, 3 + 1) = (-2, 4)
  • B' = (-5 + 2, -1 + 1) = (-3, 0)
  • C' = (0 + 2, 2 + 1) = (2, 3)

Question 8

Given vertices of the pre-image:

  • A = (-2, -4)
  • B = (-2, 4)
  • C = (2, 2)

If the pre-image is dilated by a scale factor of ¹/₂ then the transformation rule is:

  • [tex](x, y) \rightarrow \left(\frac{1}{2}x, \frac{1}{2}y\right)[/tex]

Therefore the vertices of the image are:

  • [tex]\sf A' = \left(\frac{1}{2} \cdot -2, \frac{1}{2} \cdot -4\right)= \left(-1, -2\right)[/tex]
  • [tex]\sf B' = \left(\frac{1}{2} \cdot -2, \frac{1}{2} \cdot 4\right) = \left(-1, 2\right)[/tex]
  • [tex]\sf C' = \left(\frac{1}{2} \cdot 2, \frac{1}{2} \cdot 2\right) = \left(1, 1\right)[/tex]
View image semsee45
View image semsee45

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