The number of phone calls between two nearby cities during a given time period, N , varies directly as the populations P₁ and P₂ of the two cities. If 109,000 calls are made between two cities with populations 74,000 and 189,000, how many calls are made between two cities with population 125,000 and 175,000?

You have N varying jointly with P1 and P2, such that N=109,000 for P1=74000 and P2=189000. You want to know N for P1=125000 and P2=175000.

Varies jointly

The relation "N varies jointly with P1 and P2" can be described by the equation ...

N = k·P1·P2

The value of k can be found as ...

k = N/(P1·P2)

k = 109000/(74000·189000) ≈ 7.793508×10^-6

New cities

Then the number of calls given the populations P1=125000 and P2=175000 is predicted to be ...

N = (7.793508×10^-6)(125000)(175000) ≈ 170482.982...

N ≈ 170483

About 170,483 calls are expected between cities with populations of 125 and 175 thousand.

abiolataiwo2015 abiolataiwo2015 · Answer 2 · 2023-01-16T16:10:58-05:00

If the number of phone calls between two nearby cities during a given time period. The number of calls that are made between two cities with population 125,000 and 175,000 is: 170,482,987,500.

How to find the number of calls?

Calls made between two cities with populations 74,000 and 189,000,

Call = 109,000/(74000 × 189000)

Call = 109,000 / 13,986,000,000

Call = 7.793508

Calls made between two cities with populations 125,000 and 175,000?

Calls = 7.793508 × 125000 ×175000

Calls =170,482,987,500

Therefore the calls made is 170,482,987,500.

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