Using the following equation and your results from the previous
question, calculate the enthalpy of combustion of 1 mole of
ethanol (show your workings and the correct units).
Q = m c T
Where:
Q = energy released (J)
m = mass of water (g)
C = specific heat capacity of water (4.18 J K-1 g
-1
)T = change in temperature (oC)

Results from previous : c) mass of ethanol burned = 70.3 g - 62.5 g
mass of ethanol burned = 7.8 g
molar mass of ethanol = 46.07 g/mol
moles of ethanol = 7.8 g * 1 mol/(46.07 g)
moles of ethanol = 0.169 moles
The moles of ethanol burned were 0.169 moles.