Answer :
Answer:
Net Force = 28.44 N
Acceleration = 0.33 [tex]\frac{m}{s^2}[/tex]
Explanation:
First, solve for the force of friction:
[tex]f=\mu N[/tex]
For this problem, let
[tex]\mu[/tex] = 0.32
[tex]N=mg\\N=(85\ kg)(9.8\ \frac{m}{s^2})\\N=833\ N[/tex]
So, the force of friction can be calculated as
[tex]f=(0.32)(833\ N)\\f=266.56\ N[/tex]
Because the force of friction opposes the motion, the net force can be found by subtracting the force of friction from the force applied by the truck.
[tex]F_t=F_T-F_N[/tex]
[tex]F_t=295\ N\\F_N=266.56\ N\\F_t=295\ N-266.56\ N\\F_t=28.44\ N[/tex]
Finally, rearrange Newton's second law of motion (F=ma) to find the rock's acceleration:
[tex]a=\frac{F_t}{m}\\a=\frac{28.44\ N}{85\ kg}\\a=0.33\ \frac{m}{s^2}[/tex]
