Answer:
approximately 85 feet
Step-by-step explanation:
Since s varies directly as the square of t, then the variation equation takes the form [tex]s=kt^2[/tex].
Solve for k by substituting s=144 and t=3. That is,
[tex]s=kt^2\\144=k(3)^2\\k=16.[/tex]
With k=16, then the variation equation is [tex]s=16t^2.[/tex]
To find the height, s, after 2.3 seconds, substitute t=2.3 in the equation of variation. That is,
[tex]s=16t^2\\s=16(2.3)^2\\s=16(5.29)\\s=84.64\\s\approx85.[/tex]
Hence, the height, s, after 2.3 seconds is approximately 85 feet.