Answer :
The solutions of the quadratic equation [tex]x^{2} =7x+4[/tex] are [tex]\frac{7+\sqrt{65} }{2}[/tex] and [tex]\frac{7-\sqrt{65} }{2}[/tex]
What are quadratic equations ?
[tex]ax^{2} +bx+c=0[/tex] is the form of a quadratic equation, a second-degree algebraic statement. Quadratic is a derivative of the term quad, which signifies square. In other words, a quadratic equation is a degree 2 equation.
Here the equation is
[tex]x^{2} =7x+4\\ x^{2} -7x-4=0\\[/tex]
The standard form of the quadratic equation [tex]ax^{2} +bx+c=0[/tex] and the quadratic formula used is
[tex]x=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}[/tex]
In this case [tex]a = 1, b = -7 ,c = -4[/tex].
Hence, the two roots are [tex]\frac{7+\sqrt{65} }{2}[/tex] and [tex]\frac{7-\sqrt{65} }{2}[/tex]
To learn more about quadratic equation from the given link
https://brainly.com/question/1214333
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What are the solutions of the quadratic equation? [tex]x^{2} =7x+4[/tex]
