Answer :
Answer:
(i) height: 36.6 m
(ii) BP = 36.6 m
(iii) AB = 51.8 m
(iv) AC = 73.2 m
Step-by-step explanation:
Given angles of elevation of 45° and 30° to the same point A from locations 100 m apart, you want to know the height of A, and distances BP, AB, and AC in the diagram.
Special triangles
The figure is divided into two special triangles. The one on the left is an isosceles right triangle with side lengths in the ratio 1:1:√2. The one on the right is a 30°-60°-90° triangle with side lengths in the ratio 1:√3:2. The common side AP corresponds to one ratio unit in each of these ratios.
(i) and (ii)
BP = AP = 1 ratio unit means BP : PC = 1 : √3, and ...
BP/BC = 1/(1+√3)
BP = BC/(1+√3) ≈ (100 m)/2.73205
BP ≈ 33.6 m
AP = 33.6 m . . . . . . same as BP
(iii)
AB is √2 times AP, so is ...
AB = √2 · 36.6 m
AB ≈ 51.8 m
AC
AC is 2 times AP, so is ...
AC = 2·(36.6 m)
AC = 73.2 m